Let W=h(z)
h(z) = z\uparrow\uparrow n when n approaches to infinity.
its clear that:
z^{h(z)} = h(z) then z^w = w
w = \frac1 {(ssrt(1/z))} where ssrt(x) is super square root of x.
h(z) = \frac1 {(ssrt(1/z))}
The super square root ssrt(x) has one real value when x > 1, two real values for e^{-\frac{1}{e}} < x < 1 and imaginary values when x < e^{-\frac{1}{e}}.
Example:
z=\sqrt{2}
h(\sqrt{2}) = \frac1 {ssrt\left(\frac1{\sqrt{2}}\right)}
Note that (\frac12)^{\frac12}=\frac1{\sqrt{2}} and also (\frac14)^{\frac14}=\frac1{\sqrt{2}}
Then h(z)=h(\sqrt{2})=\frac1{\frac12}=2
and also h(z)=h(\sqrt{2})=\frac1{\frac14}=4
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